Fundamentals of Wireless Communication Homework 1 Handout

Communication Technology Laboratory Fundamentals of Wireless Communications Homework 1 Solutions Problem 1 Identification of Ltv Systems

Fundamentals of Wireless Communications Homework 1 Solutions Handout date: April 1, 2014 Problem 1 Identification of LTV Systems 1. Suppose x stably identifiesQ. ForH1, H2 ∈ QwithH1x = H2xwe have 0 = H1x−H2x = (H1 −H2)x sinceH1, H2 are linear operators. Moreover,H1 −H2 ∈ Q. Since x stably identifiesQ, α‖H1 −H2‖H ≤ ‖(H1 −H2)x‖ = 0 with α > 0, which implies thatH1 −H2 = 0, i.e.,H1 = H2. 2. We sta...

Physics 171. General Relativity. Professor Dine Fall, 2008. Handout: A Primer on Curvature, the Einstein Equations and Cosmology (and Homework Set 7)

Fundamentals of Digital Communication

This textbook presents the fundamental concepts underlying the design of modern digital communication systems, which include the wireline, wireless, and storage systems that pervade our everyday lives. Using a highly accessible, lecture style exposition, this rigorous textbook first establishes a firm grounding in classical concepts of modulation and demodulation, and then builds on these to in...

Outlines of Solutions to Selected Homework Problems

This handout contains solutions and hints to solutions for many of the STA 6505 homework exercises from Categorical Data Analysis, second edition, by Alan Agresti (John Wiley, & Sons, 2002). It should not be distributed elsewhere without permission of the author. Additional solutions for odd-numbered exercises are available at the website for the text, http://www.stat.ufl.edu/∼aa/cda/cda.html. ...

Math 193a, HANDOUT FOR HOMEWORK Some Answers and Solutions

39. This exercise is a generalization of Exercise 38. Let u be a utility function, a r.v. X1 has the original distribution, and X2 has the transformed distribution. Then E{u(X1)} = ∑k u(xk)pk. The corresponding representation E{u(X2)} is the same except the terms with k = i−1, i, and i+1. Consequently, the difference E{u(X1)}−E{u(X2)}=−∆u(xi−1)+2∆u(xi)−∆u(xi+1) = 2∆ [ u(xi)− 1 2 (u(xi−1)+u(xi+1...